[Programmers] 코딩 기초 트레이닝 #4

목차

 

n보다 커질 때까지 더하기

https://school.programmers.co.kr/learn/courses/30/lessons/181884

def solution(numbers, n):
    
    latest = 0
    for number in numbers:
        latest += number
        
        if latest > n:
            return latest

 

문자열 앞의 n 글자

https://school.programmers.co.kr/learn/courses/30/lessons/181907

def solution(my_string, n):    
    return my_string[0:n]

 

문자열 뒤의 n 글자

https://school.programmers.co.kr/learn/courses/30/lessons/181910

def solution(my_string, n):
    return my_string[len(my_string) - n:]

 

0떼기

https://school.programmers.co.kr/learn/courses/30/lessons/181847

def solution(n_str):
    return n_str.lstrip("0")

 

문자열로 변환

https://school.programmers.co.kr/learn/courses/30/lessons/181845

def solution(n):
    return str(n)

 

n 번째 원소까지

https://school.programmers.co.kr/learn/courses/30/lessons/181889

def solution(num_list, n):    
    return num_list[0:n]

 

접미사인지 확인하기

https://school.programmers.co.kr/learn/courses/30/lessons/181908

def solution(my_string, is_suffix):
    length = len(my_string)
    length2 = len(is_suffix)

    answer = 0
    if length2 > length:
        answer = 0
    for x in range(length + 1):
        if is_suffix == my_string[x:length]:
            answer = 1
    return answer

def solution(my_string, is_suffix):
    return int(my_string.endswith(is_suffix))

 

문자열 바꿔서 찾기

https://school.programmers.co.kr/learn/courses/30/lessons/181864

def solution(myString, pat):
    cc = ""
    for x in myString:
        if x == 'A':
            cc += "B"
        if x == 'B':
            cc += "A"
    return int(pat in cc)

 

길이에 따른 연산

https://school.programmers.co.kr/learn/courses/30/lessons/181879

def solution(num_list):
    length = len(num_list)
    
    if 10 < length:
        return sum(num_list)
    else:
        mul = 1
        for n in num_list:
            mul *= n
        return mul

 

첫 번째로 나오는 음수

https://school.programmers.co.kr/learn/courses/30/lessons/181896

def solution(num_list):
    for num in num_list:
        if num < 0:
            return num_list.index(num)
    return -1