[Programmers] 코딩 기초 트레이닝 #7

목차

 

 

콜라츠 수열

https://school.programmers.co.kr/learn/courses/30/lessons/181919

def solution(n):
    answer = []
    while n != 1:
        answer.append(n)
        if n % 2 == 0:
            n = int(n / 2)
        else:
            n = int(3 * n + 1)
    answer.append(1)

    return answer

 

가까운 1찾기

https://school.programmers.co.kr/learn/courses/30/lessons/181898

def solution(arr, idx):    
    for x in range(idx, len(arr)):
        if arr[x] == 1:
            return x
    return -1

 

특별한 이차원 배열 1

https://school.programmers.co.kr/learn/courses/30/lessons/181833

def solution(n):
    grid = []
    for idx1 in range(0, n):
        grid.append([0 for idx2 in range(n)])

    for idx1 in range(0, n):
        grid[idx1][idx1] = 1
    
    return grid

 

ad 제거하기

https://school.programmers.co.kr/learn/courses/30/lessons/181870

def solution(strArr):
    answer = []
    for idx, value in enumerate(strArr):
        if "ad" not in value:
            answer.append(value)
    return answer

 

A 강조하기

https://school.programmers.co.kr/learn/courses/30/lessons/181874#

def solution(myString):
    myString = myString.replace("a", "A")
    
    
    for ch in myString:
        if ch != "A" and ch.isupper():
            myString = myString.replace(ch, ch.lower())
    
    return myString

 

간단한 계산기

https://school.programmers.co.kr/learn/courses/30/lessons/181865

def solution(binomial):
    return eval(binomial)

 

문자열 잘라서 정렬하기

https://school.programmers.co.kr/learn/courses/30/lessons/181866

def solution(myString):
    result = [x for x in myString.split("x") if x]
    result.sort(key=lambda x:x)

    return result

 

접미사 배열

https://school.programmers.co.kr/learn/courses/30/lessons/181909

def solution(my_string):
    result = []

    for x in range(len(my_string) - 1, -1, -1):
        if my_string[x: len(my_string)]:
            result.append(my_string[x: len(my_string)])

    result.sort(key=lambda x:x)

    return result

 

l로 만들기

https://school.programmers.co.kr/learn/courses/30/lessons/181834

def solution(myString):
    for x in myString:
        if ord(x) < ord("l"):
            myString = myString.replace(x, "l")

    return myString

 

수 조작하기 2

https://school.programmers.co.kr/learn/courses/30/lessons/181925

def solution(numLog):
    m = {1: "w", -1: "s", +10: "d", -10: "a"}

    answer = ""
    for idx in range(1, len(numLog)):
        gap = numLog[idx] - numLog[idx-1]
        answer += m[gap]
        
    return answer