[Programers] 코딩테스트 입문 #6 (with Python)

목차

커피심부름

https://school.programmers.co.kr/learn/courses/30/lessons/181837

프로그래머스

def solution(order):
    total = 0

    for x in order:

        if x.find("americano") != -1:
            total += 4500
        if x.find('cafelatte') != -1:
            total += 5000
        if x.find('anything') != -1:
            total += 4500

    return total

if __name__ == '__main__':
    print(solution(order=["cafelatte", "americanoice", "hotcafelatte", "anything"]))

 

왼쪽 오른쪽

https://school.programmers.co.kr/learn/courses/30/lessons/181890

프로그래머스

def solution(str_list):
    answer = []
    for idx, value in enumerate(str_list):

        if value == 'l':
            answer = str_list[:idx]
            break

        if value == 'r':
            answer = str_list[idx+1:]
            break
    return answer

if __name__ == '__main__':
    print(solution(["u", "u", "l", "r"]))
    print(solution(["l"]))
    print(solution(["u", "r", "u", "r"]))
    print(solution(["r", "l"]))
    print(solution(["u", "u", "r", "l", "r", "r", "r", "r"]))

 

조건에 맞게 수열 반환하기2

https://school.programmers.co.kr/learn/courses/30/lessons/181881

프로그래머스

def solution(arr):
    latest = arr
    count = 0
    for _ in range(len(arr)):
        _temp = []
        for idx, value in enumerate(latest):

            if value >= 50 and value % 2 == 0:
                t = value / 2
            elif value < 50 and value % 2 != 0:
                t = (value * 2) + 1
            else:
                t = value

            _temp.append(int(t))

        if latest != _temp:
            latest = _temp
            count += 1
        else:
            break

    return count

if __name__ == '__main__':
    print(solution(arr=[1, 2, 3, 100, 99, 98]))