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목차

     

     

    콜라츠 수열

    https://school.programmers.co.kr/learn/courses/30/lessons/181919

    def solution(n):
        answer = []
        while n != 1:
            answer.append(n)
            if n % 2 == 0:
                n = int(n / 2)
            else:
                n = int(3 * n + 1)
        answer.append(1)
    
        return answer
    

     

    가까운 1찾기

    https://school.programmers.co.kr/learn/courses/30/lessons/181898

    def solution(arr, idx):    
        for x in range(idx, len(arr)):
            if arr[x] == 1:
                return x
        return -1
    

     

    특별한 이차원 배열 1

    https://school.programmers.co.kr/learn/courses/30/lessons/181833

    def solution(n):
        grid = []
        for idx1 in range(0, n):
            grid.append([0 for idx2 in range(n)])
    
        for idx1 in range(0, n):
            grid[idx1][idx1] = 1
        
        return grid
    

     

    ad 제거하기

    https://school.programmers.co.kr/learn/courses/30/lessons/181870

    def solution(strArr):
        answer = []
        for idx, value in enumerate(strArr):
            if "ad" not in value:
                answer.append(value)
        return answer
    

     

    A 강조하기

    https://school.programmers.co.kr/learn/courses/30/lessons/181874#

    def solution(myString):
        myString = myString.replace("a", "A")
        
        
        for ch in myString:
            if ch != "A" and ch.isupper():
                myString = myString.replace(ch, ch.lower())
        
        return myString
    

     

    간단한 계산기

    https://school.programmers.co.kr/learn/courses/30/lessons/181865

    def solution(binomial):
        return eval(binomial)
    

     

    문자열 잘라서 정렬하기

    https://school.programmers.co.kr/learn/courses/30/lessons/181866

    def solution(myString):
        result = [x for x in myString.split("x") if x]
        result.sort(key=lambda x:x)
    
        return result
    

     

    접미사 배열

    https://school.programmers.co.kr/learn/courses/30/lessons/181909

    def solution(my_string):
        result = []
    
        for x in range(len(my_string) - 1, -1, -1):
            if my_string[x: len(my_string)]:
                result.append(my_string[x: len(my_string)])
    
        result.sort(key=lambda x:x)
    
        return result
    

     

    l로 만들기

    https://school.programmers.co.kr/learn/courses/30/lessons/181834

    def solution(myString):
        for x in myString:
            if ord(x) < ord("l"):
                myString = myString.replace(x, "l")
    
        return myString
    

     

    수 조작하기 2

    https://school.programmers.co.kr/learn/courses/30/lessons/181925

    def solution(numLog):
        m = {1: "w", -1: "s", +10: "d", -10: "a"}
    
        answer = ""
        for idx in range(1, len(numLog)):
            gap = numLog[idx] - numLog[idx-1]
            answer += m[gap]
            
        return answer
    
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